ΔTb=Kb× molality
ΔTb=1K
Molality =\(={moles(n)\over weightofsolvent(Kg)}\)
Molality = \(= {1 X 1000 \over 50X50} = {10 \over 25} = {2\over5} \)
1=Kb×\({2\over 5}\)
Kb=2.5 K Kg mol−1
